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Side of the curve of \( f \) We calculate in the interval \( \bigl[a, b \bigr] = [-1,1] \): $$ g(\lambda) = f\bigl(\lambda a + (1- \lambda)b\bigr) $$ So, $$ g(\lambda) = (-\lambda + (1- \lambda))^2 = \lambda -2\lambda(1- \lambda) + (1- \lambda)^2 $$$$g(\lambda) = \lambda -2\lambda + 2\lambda ^2 + 1 -2\lambda + \lambda ^2$$$$ g(\lambda) =3\lambda^2 - 3\lambda+ 1 $$ Side of the rope between \( -1 \) and \( 1 \) We calculate in the interval \( \bigl[a, b \bigr] = [-1,1] \): $$ h(\lambda) = \lambda f(a) + (1 - \lambda)f(b) $$ So, $$ h(\lambda) = \lambda (-1)^2 + (1- \lambda) 1^2 = \lambda + 1 -\lambda $$$$ h(\lambda) = 1 $$ Comparison of \( g(\lambda) \) with \( h(\lambda)\) To determine the relative position of these two functions, let's take their difference

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doi:10.1016/j.ajog.2016.01.170

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